Problem 6.5-1

As usual, we call V₁ the inverting input node voltage and V₂ the non-inverting input node voltage.

The two currents entering the op amp are equal to zero.

The KVL gives us:

V₀ = – 20. 10³ * i₀ – 5. 10³*i₀ + 3

The non-inverting node gives us:

V₂ /10³ + (V₂ – 6)/2. 10³ = 0

But we have V₂ = V₁

So we get V₁ + V₁ /2 = 6/2 =3 so V₁ =2 V

Then as V₂ = V₁ = 3 – 5. 10³*i₀ = 2 then we get i₀ = 0.2 mA

And finally V₀ = – 20*0.2 + V₁ = – 2 V