As usual, we call V1 the inverting input node voltage and V2
the non-inverting input node voltage.
The two currents entering the op amp are equal to zero.
At the non-inverting node we have:
– (V2 + 4)/4. 103 + 2. 10-3 = 0
thus 8 = V2 + 4 so V2 = V1 = 4V
From the KVL we get V0 = – 24. 103 *i0
– 8. 103*i0 + 3
And V1 = – 8. 103*i0 + 3 = V2
= 4V
Thus i0 = – 1/8 mA
So we get V0 = 24/8 + 8/8+ 3 = 7V