As usual, we call V1 the inverting input node voltage and V2
the non-inverting input node voltage.
The two currents entering the op amp are equal to zero.
The KVL gives us:
V0 = – 20. 103 * i0 – 5. 103*i0
+ 3
The non-inverting node gives us:
V2 /103 + (V2 – 6)/2. 103 =
0
But we have V2 = V1
So we get V1 + V1 /2 = 6/2 =3 so V1 =2
V
Then as V2 = V1 = 3 – 5. 103*i0
= 2 then we get i0 = 0.2 mA
And finally V0 = – 20*0.2 + V1 = – 2 V