Then we have two resistors in series, one of 4Ω and Req1 of 2Ω so we get R1 = 2 + 4 = 6Ω.
Then we have Req2 in series with a 8Ω resistor, thus we have: R2 = 12/5 + 8 = 52/5 Ω
So 24 = i1*R2 + 6*(i1-2) so we get i1 = 36*5/82 = 2.19 A
Then we can find the voltage v1 = i1*R2 = (36*5/82)*(52/5) = 36*26/41 = 22.8 V