Let’s call node 1, the node on the left, corresponding to the
non-inverting entry of the left op amp. Let’s call node 2, the node on the
right, corresponding to the inverting entry of the right op amp.
The KCL gives us, for node 1:
(V1 – V)*C1s + (V1 – V0)/R1
= 0 (1)
The KCL gives us, for node 2:
(V2 – V1)/R2 + (V2 – V0)*C2s
= 0 (2)
But we have V2 = 0 thus we get from (2)
V1 = – V0 R2C2s
We replace that in equation (1) and we
get