We use the table on page p.600 of the textbook to get the network
function.
The second circuit is what we are looking for, so for fig. 13.3-5 we
get:
where p is given by 1/C2R2, so we have p =
1/(50.103*2.10-6) = 10,
and k = R2/R1 so here k = 50/10 = 5
thus we get: